Catalan Solid and Its Generalization

Jen-chung Chuan

 jcchuan@gmail.com

http://140.114.32.246/d2/ATCM%202015/

 

 

Introduction

A Catalan solid is a dual polyhedron to an Archimedean solid. A list of 13 Catalan solids together with their Archimedean duals can be found in Wikipedia: https://en.wikipedia.org/wiki/Catalan_solid In this talk, we are to show the most efficient ways to construct all 13 dual pairs of polyhedrons, under the environment provided by the dynamic solid geometry software Cabri 3D. We then proceed to show with animations how each of such dual pairs can be distorted to form other generalized dual-pair polyhedrons families. Here we adopt the notion that two polyhedrons A and B are said to form a (generalized) dual pair if they have the same number of edges and each edge of A intersects a unique edge of B orthogonally in space.

Results

 

Archimedean Solid

Castalan Solid

 

Duality

Orthogonality Preserving Distortion­

truncated tetrahedron

triakis tetrahedron

 

描述 : Server HD:Users:jcchuan:Desktop:ATCM 2015:truncated tetrahedron and its dual  triakis tetrahedron_html.png

Orthogonality Preserving Distorsion of Truncated Tetrahedron-Triakis Tetrahedron_html

truncated cube

triakis octahedron

 

描述 : Server HD:Users:jcchuan:Desktop:ATCM 2015:truncated cube and its dual triakis octahedron_html.png

Orthogonality Preserving Distorsion of Truncated Cube-Triakis Octahedron_html

truncated cuboctahedron

disdyakis dodecahedron

 

truncated cuboctahedron and its dual disdyakis dodecahedron_html

Orthogonality Preserving Distorsion of Truncated Cuboctahedron-Disdyakis Dodecahedron_html

truncated octahedron

tetrakis hexahedron

 

truncated cuboctahedron and its dual disdyakis dodecahedron_html

Orthogonality Preserving Distorsion of Truncated Octahedron-Tetrakis Hexahedron_html

truncated dodecahedron

triakis icosahedron

 

truncated dodecahedron and its dual triakis icosahedron_html

 

truncated icosidodecahedron

disdyakis triacontahedron

 

 truncated icosidodecahedron and Its dual disdyakis triacontahedron_html

 

truncated icosahedron

pentakis dodecahedron

 

truncated icosahedron and its dual pentakis dodecahedron_html

 

cuboctahedron

rhombic dodecahedron

 

cuboctahedron and its dual rhombic dodecahedron_html

Orthogonal Preserving Distorsion of Cuboctahedron-Rhombic dodecahedron_html

icosidodecahedron

rhombic triacontahedron

 

icosidodecahedron and its dual rhombic triacontahedron_html

Orthogonality Preserving Distorsion of Icosahedron-Rhombic Triacontahedron_html

rhombicuboctahedron

deltoidal icositetrahedron

 

rhombicosidodecahedron

deltoidal hexecontahedron

 

rhombicosidodecahedron and its dual deltoidal hexecontahedron_html

Orthogonality Preserving Distorsion of Rhombicosidodecahedron-Deltoidal Hexecontahedron_html

snub tetrahedron

pentagonal icositetrahedron

 

snub dodechedron

pentagonal hexecontahedron

 

 

 

Orthogonal Preserving Distortion of
Regular Poyhedron and Its Dual

Tetrahedron and Its Dual_html

Orthogonal Preserving Distortion of Tetrahedron and Its Dual

Orthogonal Distorsion of Cube-Octahedron_html

Orthogonal Distortion of Cube-Octahedron

Orthogonal Distorsion of Dodecahedron-Icosahedron_html

Orthogonality Preserving Distortion of Dodecahedron-Icosahedron

 

 


 

Orthogonal Preserving Distortion of Other Pairs

 

Distortion

Triangular Cupola

Some Distorted Triangular Cupola Has Dual

Square Cupola

Some Distorted Square Cupola Has Dual

Pentagonal Cupola

Some Distorted Pentagonal Cupola Has Dual

Triangular Orthobicupola

Triangular Orthobicupola-Trapezo-Rhombic Dodecahedron Distorted Symmetrically

 

Process of Distortion

Step 1. Construct the most symmetric pair of dual polyhedrons.

 

 

Step 2. Since all edges are tangent to a same sphere S, their faces meet S in two orthogonal families of circles.


 

1.    

Step 3. By taking inversion of circles with respect to S, two orthogonal families of circles are transformed to two new orthogonal families of circles.

Step 4. Construct the two polyhedrons corresponding two the circles.